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Proof step 14 from proof heap-order-overwrite-children-at (previous step)

kar[2 * m + 1] = key-index(key3, m5), kar[m, key-index(key, m0)][m1 / 2] = key-index(key1, m3), kar[m, key-index(key, m0)][m1 + 1] = key-index(key0, m2), kar[2 * m + 2] = key-index(key2, m4), kar[(m - 1) / 2] = key-index(key4, m6), m1 + 1 < # kar, m < # kar, m1 + 1 < n, key0 < key1, m < n, n ≤ # kar, m ≠ 0 → ¬ key < key4, 2 * m + 1 < n → ¬ key3 < key, 2 * m + 2 < n → ¬ key2 < key ⊦ kar[m1 + 1].key < kar[m1 / 2].key

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 15:
kar[(m - 1) / 2] = key-index(key4, m6), kar[2 * m + 2] = key-index(key2, m4), kar[m, key-index(key, m0)][m1 + 1] = key-index(key0, m2), kar[m, key-index(key, m0)][m1 / 2] = key-index(key1, m3), kar[2 * m + 1] = key-index(key3, m5), kar[m1 + 1] = key-index(key5, m7), m < n, key0 < key1, m1 + 1 < n, m < # kar, m1 + 1 < # kar, n ≤ # kar, 2 * m + 2 < n → ¬ key2 < key, 2 * m + 1 < n → ¬ key3 < key, m ≠ 0 → ¬ key < key4 ⊦ key5 < kar[m1 / 2].key

Rule argument

spec: key-index name: elim seq: ⊦ key = ki.key ∧ m = ki.idx ↔ ki = key-index(key, m) subst: [ki, key, m] → [kar[m1 + 1], key5, m7]

Additional information

Used simplifier rules: ⊦ key = ki.key ∧ m = ki.idx ↔ ki = key-index(key, m); (elim) Used terms: kar[m1 + 1], key5, m7