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Proof step 12 from proof heap-order-overwrite-parent-ok (previous step)

kar[m0 + 1, key-index(key, m2)][m1 / 2] = key-index(key1, m4), kar[m0 + 1, key-index(key, m2)][m1 + 1] = key-index(key0, m3), kar[m0 + 1] = key-index(key2, m5), m0 + 1 < # kar, m1 + 1 < # kar, m1 + 1 < n, key0 < key1, m0 + 1 < n, n ≤ # kar, ∀ m. m < n ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ key2 < kar[m0 / 2].key, key < kar[m0 / 2].key, key2 < key

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 13:
kar[m0 + 1] = key-index(key2, m5), kar[m0 + 1, key-index(key, m2)][m1 + 1] = key-index(key0, m3), kar[m0 + 1, key-index(key, m2)][m1 / 2] = key-index(key1, m4), kar[m0 / 2] = key-index(key3, m6), m0 + 1 < n, key0 < key1, m1 + 1 < n, m1 + 1 < # kar, m0 + 1 < # kar, n ≤ # kar, ∀ m. m < n ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ key2 < key, key < key3, key2 < key3

Rule argument

spec: key-index name: elim seq: ⊦ key = ki.key ∧ m = ki.idx ↔ ki = key-index(key, m) subst: [ki, key, m] → [kar[m0 / 2], key3, m6]

Additional information

Used simplifier rules: ⊦ key = ki.key ∧ m = ki.idx ↔ ki = key-index(key, m); (elim) Used terms: kar[m0 / 2], key3, m6