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Proof step 18 from proof heap-order-pull-down-parent (previous step)

kar[m1 + 1, kar[m1 / 2]][m2 + 1] = key-index(key, m0), kar[m2 / 2] = key-index(key0, m3), m1 + 1 < n, key < key0, m2 + 1 < n, m1 + 1 < # kar, m2 + 1 < # kar, n ≤ # kar, ∀ m. m < n ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ m2 / 2 = m1 + 1

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 19:
kar[m2 / 2] = key-index(key0, m3), kar[m1 + 1, kar[m1 / 2]][m2 + 1] = key-index(key, m0), m2 + 1 < # kar, m1 + 1 < # kar, m2 + 1 < n, key < key0, m1 + 1 < n, n ≤ # kar, ∀ m. m < n ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ m2 + 1 = m1 + 1, m2 / 2 = m1 + 1

Rule argument

fma: m2 + 1 = m1 + 1

Additional information

Used simplifier rules: ⊦ m + n = m + n0 ↔ n = n0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m < # kar → kar[m, ki][m] = ki; (s)% ⊦ m / 2 ≠ m + 1; (s)% ⊦ key-index(key, m) = key-index(key0, m0) ↔ key = key0 ∧ m = m0; (ws)%lel: ⊦ key < key0 ∧ key = key1 → key1 < key0; (forward) from specification oelem[binheap-key]% ⊦ ¬ key < key; (s) Used formulas: m2 + 1 = m1 + 1