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Proof step 12 from proof key-set-extract-index (
previous step
)
n0 < # kar, m < # kar, m ≤ n0 ⊦ kar[m] = kar[n0], kar[m] ∈ keyset(kar, n0), ∃ m0. m0 < n0 ∧ kar[m] = kar[m0]
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 3 terms: m
Additional information
Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: m