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Proof step 1 from proof no-dups-idx-rec (conclusion)

⊦ n < # kar ∧ no-dups-idx(kar, n) → (no-dups-idx(kar[n, ki], n + 1) ↔ ¬(∃ ki0. ki0 ∈ keyset(kar, n) ∧ ki0.idx = ki.idx))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information