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Proof step 26 from proof valid-idx-move-last (previous step)

ar[m1, ar[m1].idx:= m0][m1] = elemindex(a, m4), kar[m] = key-index(key, m1), m0 < # kar, m < # kar, m0 < m, m0 + 1 < # kar, # ar ≤ m1, ∀ m2. ¬ m < m2 → kar[m2].idx < # ar ∧ ar[kar[m2].idx].idx = m2 ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 8 terms: m abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic% ⊦ key-index(key, m).idx = m; (s)% ⊦ m < n → n ≠ 0; (s) Used terms: m