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Proof step 5 from proof div2-mult4-add-k (previous step)

⊦ (4 * n) % 2 = 0, (n0 + 4 * n) / 2 = n0 / 2 + 2 * n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n))
Proof step 7:
⊦ (n0 + 4 * n) / 2 = n0 / 2 + 2 * n, 2 = 0, ∃ n0. 4 * n = n0 * 2

Rule argument

spec: nat-div name: modex seq: ⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n)) subst: [n, m] → [2, 4 * n] flags: <all paths>

Additional information

Used terms: 2, 4 * n