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Proof step 8 from proof div2-mult4-add-k (previous step)

⊦ (n0 + 4 * n) / 2 = n0 / 2 + 2 * n, ∃ n0. 4 * n = n0 * 2

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: 2 * n abort: F discard: T computed: F

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult% ⊦ m * n = m * n0 ↔ m = 0 ∨ n = n0; (ws) Used terms: 2 * n