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Proof step 83 from proof prepost-bubble-down (
previous step
)
m ≤ # kar ⊦ n0 < m ∧ n1 < m ∧ kar[n0] = ki1 ∧ kar[n1] = ki0 → keyset(kar[n0, ki0][n1, ki1], m) = keyset(kar, m)
A spec-lemma