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Proof step 4 from proof prepost-next2pot (previous step)

2exp-size(n) ⊦ ⟪while n < minsize do n := n * 2⟫ (2exp-size(n) ∧ minsize ≤ n)

User applied rule invariant right

And obtained the following new goals

Rule argument

bound: (n ≥ minsize ⊃ 0;minsize - n) inv: 2exp-size(n) fmapos: right 1

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss) Used formulas: 2exp-size(n), (n ≥ minsize ⊃ 0;minsize - n) = (n ≥ minsize ⊃ 0;minsize - n)