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Proof step 63 from proof prepost-update (previous step)

m4 / 2 = m3 + 1, kar[m4 / 2] = key-index(key5, m7), kar[m3 + 1, key-index(key0, m2)][m4 + 1] = key-index(key2, m1), ar[m] = elemindex(a, m3 + 1), kar[m3 + 1] = key-index(key1, m), kar[m3 / 2] = key-index(key0, m2), kar[m3 + 1, key-index(key0, m2)][m4 / 2] = key-index(key3, m5), kar[m4 + 1] = key-index(key4, m6), 2exp-size(# kar), key2 < key3, m4 + 1 < m0, m3 + 1 < m0, key < key1, key < key0, m3 + 1 < # kar, m4 + 1 < # kar, no-dups-idx(kar, m0), valid-idx(kar, ar, m0), key-index(key1, m) ∈ keyset(kar, m0), m0 ≤ # kar, ∀ m. m < m0 ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ # keyset(kar, m0) = 0, keyset(kar, m0) = ∅, key4 < key5

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 64:
m4 / 2 = m3 + 1, kar[m3 + 1] = key-index(key1, m), kar[m4 + 1] = key-index(key4, m6), ar[m] = elemindex(a, m3 + 1), kar[m3 / 2] = key-index(key3, m2), 2exp-size(# kar), key1 < key3, m4 + 1 < m0, m3 + 1 < m0, key < key1, m3 + 1 < # kar, m4 + 1 < # kar, key4 < key3, key < key3, no-dups-idx(kar, m0), valid-idx(kar, ar, m0), key-index(key1, m) ∈ keyset(kar, m0), m0 ≤ # kar, ∀ m. m < m0 ∧ m ≠ 0 → ¬ kar[m].key < kar[(m - 1) / 2].key ⊦ # keyset(kar, m0) = 0, keyset(kar, m0) = ∅, key4 < key1

Rule argument

Additional information

Used simplifier rules: transitivity: ⊦ key < key0 ∧ key0 < key1 → key < key1; (forward) from specification oelem[binheap-key]%nll: ⊦ ¬ key < key0 ∧ key < key1 → key0 < key1; (forward) from specification oelem[binheap-key]%nen: ⊦ ¬ key < key0 ∧ key0 = key1 → ¬ key < key1; (forward) from specification oelem[binheap-key]%lel: ⊦ key < key0 ∧ key = key1 → key1 < key0; (forward) from specification oelem[binheap-key]% ⊦ m < # kar → kar[m, ki][m] = ki; (s)% ⊦ key-index(key, m) = key-index(key0, m0) ↔ key = key0 ∧ m = m0; (ws)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%m ≠ n ⊦ kar[m, ki][n] = kar[n]; (s)% ⊦ m / 2 ≠ m + 1; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)