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Proof step 8 from proof id-idx-trans (previous step)

# ar1 = # ar0, # ar2 = # ar0, ar2[n] = elemindex(a0, m0), ar0[n] = elemindex(a, m), ar1[n] = elemindex(a, m1), n < # ar0, ∀ n. n < # ar0 → ar1[n].elem = ar2[n].elem ⊦ a = a0

User applied rule all left

And closed the goal!

Rule argument

pos: left 7 terms: n abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ elemindex(a, m).elem = a; (s) Used terms: n