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Proof step 10 from proof id-idx-write-left (previous step)

# ar0 = # ar1, ∀ n. n < # ar1 → ar1[n].elem = ar0[n].elem ⊦ ∀ n. n < # ar1 → ar1[m, ar1[m].idx:= m0][n].elem = ar0[n].elem

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# ar0 = # ar1, n < # ar1, ∀ n. n < # ar1 → ar1[n].elem = ar0[n].elem ⊦ ar1[m, ar1[m].idx:= m0][n].elem = ar0[n].elem

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic