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Proof step 5 from proof disj-union-rem (previous step)

n1 < # asar, n0 < # asar, n1 < m, n0 < m, disj(asar, 0, m), m ≤ # asar ⊦ n0 = n1, ∀ adr. adr ∈ (asar[n0] ∪ as) \ asar[n1] ↔ adr ∈ asar[n0] ∪ (as \ asar[n1])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n0 < m, n1 < m, n0 < # asar, n1 < # asar, disj(asar, 0, m), m ≤ # asar ⊦ adr ∈ (asar[n0] ∪ as) \ asar[n1] ↔ adr ∈ asar[n0] ∪ (as \ asar[n1]), n0 = n1

Proof step 5 from proof disj-union-rem (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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