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Proof step 2 from proof disj-unique (previous step)

n1 < # asar, n0 < # asar, disj(asar, 0, # asar), adr ∈ asar[n0] ⊦ adr ∈ asar[n1] ↔ n0 = n1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: disj-in-both: n0 < m, n1 < m ⊦ disj(asar, 0, m) ∧ adr ∈ asar[n0] → (adr ∈ asar[n1] ↔ n0 = n1);