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Proof step 21 from proof disj-write (previous step)

n0 < # asar, n1 < # asar, n < # asar, n < m, n0 < m, n1 < m, m ≤ # asar, ∀ n0, n1. n0 < m ∧ n1 < m ∧ n0 ≠ n1 → asar[n0] ∩ asar[n1] = ∅, ∀ n0. n0 ≠ n ∧ n0 < m → asar[n0] ∩ as = ∅ ⊦ #(asar[n1] ∩ asar[n0]) = 0, n0 = n, n1 = n, n1 = n0, asar[n1] ∩ asar[n0] = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 8 terms: n1, n0

Additional information

Used terms: n1, n0