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Proof step 6 from proof in-index-in-union-1 (previous step)

adr ∈ asar[n], n ≤ m ⊦ # asar[n] = 0, asar[n] = ∅, adr ∈ asar[m], ∃ n0. n0 < m ∧ adr ∈ asar[n0]

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 4 terms: n

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: n