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Proof step 4 from proof in-union-ext (previous step)

adr ∈ union(asar, n, m0) ↔ (∃ n0. n ≤ n0 ∧ n0 < n + m0 ∧ adr ∈ asar[n0]) ⊦ adr ∈ asar[n + m0] ∪ union(asar, n, m0) ↔ (∃ n0. n ≤ n0 ∧ ¬ n + m0 < n0 ∧ adr ∈ asar[n0])

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information