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Proof step 2 from proof union-eq-rem-subseteq (previous step)

union(asar, 0, # asar) = as -- adr, n < # asar ⊦ asar[n] ⊆ as

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
union(asar, 0, # asar) = as -- adr, n < # asar ⊦ asar[n] ⊆ as

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic