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Proof step 7 from proof union-subset (previous step)

n0 ≤ n + m0, n ≤ n0, union(asar, n, m0) ⊆ as, asar[n + m0] ⊆ as, ∀ n0. n ≤ n0 ∧ n0 < n + m0 → asar[n0] ⊆ as ⊦ asar[n0] ⊆ asar[n + m0], asar[n0] ⊆ union(asar, n, m0), asar[n0] ⊆ as

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s) Used terms: n0