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Proof step 75 from proof inv-commit (previous step)

syn ↔ syn0, istore2[m0] = indexblock(indx, lax, m3), zh[rp] = mkznode(r, zbrar, boolvar, true, m), zh0[rp] = mkznode(r0, zbrar0, boolvar0, false, m4), ginval0 = ginval4, gstore = gstore1, gstore0 = gstore2, istore = istore2, istore0 = istore1, maxino = maxino1, maxino0 = m0, n = istore2[m0].ref-size - m2, pstate = readonly, remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval4 = ∅, dom remove-refsize0(gstore2) ∩ ginval4 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval4, btree-inv(rp, adr, istore3[n0, indexblock([], [], 0)], istore1, zh, ri, fi), btree-inv(rp, adr, istore3, istore1, zh, ri, fi), btree-inv(rp, @(m0, m1, m2), istore2, istore2, zh0, ri, ri), btree-inv(rp, adr, istore2[m0, indexblock(indx, lax, m3 - m2)], istore1, zh0[rp, mkznode(r0, zbrar0, boolvar0, true, m4)], ri, fi), inv(istore3[n0, indexblock([], [], 0)]), inv(istore1), inv(istore3), inv(gstore1), inv(gstore2 \ ginval4), inv(istore2), inv(indexblock(indx, lax, m3)), m0 ∈ istore2, rp ∈ zh, istore2[m0].ref-size ≥ m2, istore1 ⊑ istore2, istore1 ⊑ istore3[n0, indexblock([], [], 0)], istore1 ⊑ istore3, istore3[n0, indexblock([], [], 0)] ⊑ istore2 ⊦ [istore[maxino0].ref-size := n] (inv(istore) ∧ istore1 ⊑ istore → (∃ ri0, fi0. btree-inv(rp, adr, istore, istore1, zh0[rp, mkznode(r0, zbrar0, boolvar0, true, m4)], ri0, fi0))), dups(nx), n0 ∈ istore3

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

Additional information