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Proof step 13 from proof inv-deallocate-gnd (previous step)

syn ↔ true, istore = istore1, istore0 = istore2, remove-refsize0(gstore0) = gstore0, remove-refsize0(istore1) = istore1, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, btree-inv(rp, adr, istore2, istore1, zh, ri, fi), inv(gstore \ ginval), inv(gstore0), inv(istore2), inv(istore1), n ∈ gstore, n ∈ gstore0, istore1 ⊑ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore, pstate.index? → pstate.lnum ∈ istore2 ⊦ dups(nx), n ∈ nx, ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
remove-refsize0(istore1) = istore1, remove-refsize0(gstore0) = gstore0, elems nx ∩ ginval = ∅, dom gstore0 ∪ elems nx = dom gstore ∪ ginval, btree-inv(rp, adr, istore2, istore1, zh, ri, fi), inv(istore1), inv(istore2), inv(gstore0), inv(gstore \ ginval), n ∈ gstore0, n ∈ gstore, istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore ⊦ dups(nx), n ∈ nx, ∃ err0. ⌊err0⌋ ∨ err0 = ESUCCESS

Proof step 13 from proof inv-deallocate-gnd (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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