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Proof step 257 from proof inv-format (previous step)

syn ↔ true, err = err0, err1 = err, ginval = ∅, ginval0 = ∅, gstore = ∅, gstore0 = ∅, ind = indexnode(mkbrarray(BRANCH_SIZE), true, 0), istore = ∅, istore0 = ∅, istore1 = istore, maxino = maxino4, nx = [], pstate = unbuffered, inv(istore), indexnode(mkbrarray(BRANCH_SIZE), true, 0).flashsize ≤ LEB_SIZE, pstate.index? → pstate.lnum ∈ istore, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪skip⟫ ( ( err1 = ESUCCESS → syn ∧ (∃ ri, fi. btree-inv(null, adr, istore1, istore0, zh, ri, fi)) ∧ inv(gstore0 \ ginval0) ∧ inv(gstore) ∧ elems nx ∩ ginval0 = ∅ ∧ ¬ dups(nx) ∧ dom gstore ∪ elems nx = dom gstore0 ∪ ginval0 ∧ remove-refsize0(gstore) = gstore ∧ inv(istore1) ∧ inv(istore0) ∧ istore0 ⊑ istore1 ∧ remove-refsize0(istore0) = istore0 ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore0) ∧ (pstate.index? → pstate.lnum ∈ istore1)) ∧ (err1 = ESUCCESS ∨ ⌊err1⌋ ) ∧ (err1 = ESUCCESS → btree-inv(null, adr, istore1, istore0, zh, ∅, ∅) ∧ gstore0 = ∅ ∧ ginval0 = ∅ ∧ maxino = maxino4 ∧ nx = [] ∧ ginval = ∅)), err = ESUCCESS, pstate.journal?

Heuristic symbolic execution applied rule skip right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ inv(∅); (s)% ⊦ ¬ unbuffered.journal?; (s)% ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)% ⊦ ¬ unbuffered.index?; (s)