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Proof step 104 from proof inv-io-save (previous step)

zh[r] = mkznode(r0, zbrar, boolvar, true, m0), adr2 = adr1, adr3 = @(pstate0.lnum, maxino, ind.flashsize), err0 = err, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, ind = save(mkznode(r0, zbrar, boolvar, true, m0)), istore = istore3[n, indexblock([], [], 0)], istore0 = istore2, pstate = readonly, pstate0 = index(n), remove-refsize0(gstore1) = gstore1, remove-refsize0(istore2) = istore2, syn0, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, ((btree(rp, r, adr1, height, dirty, ri, nodes(istore3), as, alladrs, ok) * P))(zh), n0 < save(mkznode(r0, zbrar, boolvar, true, m0)).flashsize, btree-sub-clean(r, m0, zh), inv(istore), inv(gstore2 \ ginval2), inv(gstore1), inv(istore3), inv(istore2), inv(istore3[n, indexblock([], [], 0)]), refsize-cons(istore3, as0 ∪ as), r ∈ zh, m ∈ istore3, n0 ≤ LEB_SIZE, as0 ⊆ dom nodes(istore3), alladrs ⊆ dom nodes(istore3), as ⊆ alladrs, as ⊆ dom nodes(istore3), istore2 ⊑ istore, istore2 ⊑ istore3, istore2 ⊑ istore3[n, indexblock([], [], 0)], pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, pstate.index? → pstate.lnum ∈ istore, pstate = unbuffered → syn, height = 0 → as = ∅, pstate0.index? ∨ pstate0.journal?, ¬ @(pstate0.lnum, maxino, ind.flashsize) ∈ istore ∧ err = ESUCCESS ∨ ⌊err⌋ ⊦ ⟪if err0 = ESUCCESS then zh[r].dirty := false⟫ ( refsize-cons(istore, as0 ∪ (err0 = ESUCCESS ⊃ as ++ adr;as)) ∧ inv(istore) ∧ istore2 ⊑ istore ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2) ∧ (pstate.index? → pstate.lnum ∈ istore) ∧ (pstate = unbuffered → syn) ∧ istore3 ⊑ istore ∧ r ∈ zh ∧ (err0 = ESUCCESS → ¬ adr ∈ as) ∧ dom nodes(istore) = dom nodes(istore3) ∪ (err0 = ESUCCESS ⊃ ∅ ++ adr;∅) ∧ (err0 = ESUCCESS → ¬ adr ∈ istore3) ∧ (( btree (rp, r, (err0 = ESUCCESS ⊃ adr;adr1), height, err0 ≠ ESUCCESS, ri, nodes(istore), (err0 = ESUCCESS ⊃ as ++ adr;as), (err0 = ESUCCESS ⊃ (alladrs -- adr1) ++ adr;alladrs), ok) * P) )(zh) ∧ (err0 = ESUCCESS ∨ ⌊err0⌋ ) ∧ (err0 = ESUCCESS → pstate.index? ∧ ¬ zh[r].dirty)), err0 = ESUCCESS, dups(nx), adr1 ∈ as, n ∈ istore3

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Rule argument

pos: right 1

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