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Proof step 205 from proof inv-io-save (previous step)

syn ↔ err = ESUCCESS, zh[r] = mkznode(r0, zbrar, boolvar, true, m0), adr = adr1, err = err0, gstore0 = gstore2, istore1 = istore3, pstate = readonly, pstate0 = index(m), remove-refsize0(istore2) = istore2, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, ((btree(rp, r, adr1, height, dirty, ri, nodes(istore3), as, alladrs, ok) * P))(zh), n < save(mkznode(r0, zbrar, boolvar, true, m0)).flashsize, btree-sub-clean(r, m0, zh), inv(istore2), inv(istore3), inv(gstore1), inv(gstore2 \ ginval2), refsize-cons(istore3, as0 ∪ as), m ∈ istore3, r ∈ zh, n ≤ LEB_SIZE, as ⊆ dom nodes(istore3), as ⊆ alladrs, alladrs ⊆ dom nodes(istore3), as0 ⊆ dom nodes(istore3), istore2 ⊑ istore3, height = 0 → as = ∅, pstate = unbuffered → syn, pstate.index? → pstate.lnum ∈ istore3, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err = ESUCCESS then zh[r].dirty := false⟫ ( refsize-cons(istore3, as0 ∪ (err = ESUCCESS ⊃ as ++ adr;as)) ∧ inv(istore3) ∧ istore2 ⊑ istore3 ∧ (pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2) ∧ (pstate.index? → pstate.lnum ∈ istore3) ∧ (pstate = unbuffered → syn) ∧ istore1 ⊑ istore3 ∧ r ∈ zh ∧ (err = ESUCCESS → ¬ adr ∈ as) ∧ dom nodes(istore3) = dom nodes(istore1) ∪ (err = ESUCCESS ⊃ ∅ ++ adr;∅) ∧ (err = ESUCCESS → ¬ adr ∈ istore1) ∧ (( btree (rp, r, (err = ESUCCESS ⊃ adr;adr1), height, err ≠ ESUCCESS, ri, nodes(istore3), (err = ESUCCESS ⊃ as ++ adr;as), (err = ESUCCESS ⊃ (alladrs -- adr1) ++ adr;alladrs), ok) * P) )(zh) ∧ (err = ESUCCESS ∨ ⌊err⌋ ) ∧ (err = ESUCCESS → pstate.index? ∧ ¬ zh[r].dirty)), err = ESUCCESS, dups(nx), adr1 ∈ as

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Rule argument

pos: right 1

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