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Proof step 6 from proof inv-read-gblock (previous step)

ginval = ginval1, ginval0 = ginval2, gstore = gstore1, gstore0 = gstore2, istore = istore1, istore0 = istore2, maxino = maxino1, maxino0 = maxino2, remove-refsize0(istore1) = istore1, remove-refsize0(gstore1) = gstore1, elems nx ∩ ginval2 = ∅, dom gstore1 ∪ elems nx = dom gstore2 ∪ ginval2, btree-inv(rp, adr, istore2, istore1, zh, ri, fi), inv(istore1), inv(istore2), inv(gstore1), inv(gstore2 \ ginval2), maxino2 ∈ gstore2, istore1 ⊑ istore2, pstate = unbuffered → syn, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx ≠ [] ∧ pstate.lnum = nx.last ∧ pstate.lnum ∈ gstore2 ⊦ ⟪if maxino0 ∈ gstore0 ∧ ¬ maxino0 ∈ ginval0 then {fail_or_success#(; ; err); if err = ESUCCESS then ax := ax + gstore0[maxino0].ladrlist.to-adr(maxino0), gndx := gndx + gstore0[maxino0].gndlist else ax := ?, gndx := ?} else abort⟫ true, dups(nx), maxino2 ∈ ginval2

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Rule argument

pos: right 1

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