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Proof step 32 from proof btree-clean-fwd-strong (previous step)

# asar0 = m + 1, # asar = m + 1, # zbrar0 = BRANCH_SIZE, union(asar0, 0, m + 1) = alladrs0 -- adr, union(asar, 0, m + 1) = alladrs0 -- adr, (( (λ n. ⌜zbrar0[n].branch?⌝ ∧ btree(r2, zbrar0[n].child, zbrar0[n].adr, height, false, key-range(zbrar0, n, m + 1, ri0), iast0, asar[n], asar0[n], ok) )⊗_ (0, m + 1 ) * P0) )(zh), (( ( ⌜0 + m + 1 ≤ m + 1 ∧ m + 1 ≤ # zbrar ∧ # zbrar = BRANCH_SIZE⌝ ∧ ⌜m + 1 ≠ 0 ∧ sorted(zbrar, 0, m + 1 - 1)⌝ ∧ _∃ (λ asar. _∃ (λ asar0. ⌜ # asar = m + 1 ∧ disj(asar, 0, m + 1) ∧ union(asar, 0, m + 1) = alladrs1 -- adr ∧ # asar0 = m + 1 ∧ disj(asar0, 0, m + 1) ∧ union(asar0, 0, m + 1) = alladrs1 -- adr ⌝ ∧ (λ n. ⌜zbrar[n].branch?⌝ ∧ btree(r, zbrar[n].child, zbrar[n].adr, height0, false, key-range(zbrar, n, m + 1, ri1), iast1, asar[n], asar0[n], ok) )⊗_ (0, m + 1 )))) * P1) )(zh3), m < BRANCH_SIZE, ((r => mkznode(rp1, zbrar, false, false, m + 1)))(zh4), ((r2 => mkznode(rp0, zbrar0, false, false, m + 1)))(zh5), disj(asar0, 0, m + 1), disj(asar, 0, m + 1), nsize(m + 1, nstat), sorted(zbrar0, 0, m), unmodified(adr, mkznode(rp0, zbrar0, false, false, m + 1), iast0), unmodified(adr, mkznode(rp1, zbrar, false, false, m + 1), iast1), adr ∈ alladrs0, adr ∈ iast0, adr ∈ alladrs1, adr ∈ iast1, iast0 ⊆ iast1, alladrs0 ⊆ dom iast0, alladrs1 ⊆ dom iast1, zh4 ⊥ zh3, zh5 ⊥ zh, (r1 = null ⊃ P1(zh1);r = r1 ∧ zh4 ∪ zh3 = zh1), (r0 = null ⊃ P0(zh0);r2 = r0 ∧ zh5 ∪ zh = zh0), ∀ rp1, r1, adr, height1, ri1, iast1, alladrs1, nstat, P1, zh1, rp0, r0, ri0, iast0, alladrs0, P0, zh0. ((btree(rp1, r1, adr, height1, false, ri1, iast1, alladrs1, alladrs1, nstat) * P1))(zh1) ∧ ((btree(rp0, r0, adr, height, false, ri0, iast0, alladrs0, alladrs0, nstat) * P0))(zh0) ∧ alladrs1 ⊆ dom iast1 ∧ alladrs0 ⊆ dom iast0 ∧ iast0 ⊆ iast1 → height = height1 ∧ ri0 = ri1 ∧ alladrs0 = alladrs1 ⊦ # alladrs0 = 0, # alladrs1 = 0, alladrs0 = ∅, alladrs1 = ∅, height = height0 ∧ ri0 = ri1 ∧ alladrs0 = alladrs1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic%eqle-one: ⊦ m = n + 1 ∧ n < n0 → m ≤ n0; (forward) from specification nat% ⊦ ((_∃ Pa0 * P0))(zh) ↔ (∃ asar. ((Pa0(asar) * P0))(zh)); (s)% ⊦ ⌜bv⌝ (zh) ↔ bv; (s)% ⊦ ((P ∧ P2))(zh) ↔ P(zh) ∧ P2(zh); (s)%sep-com: ⊦ P * P2 = P2 * P; from specification heap-sep[zheap]%sep-ass: ⊦ (P * P3) * P4 = P * P3 * P4; from specification heap-sep[zheap]%and-com: ⊦ (P ∧ P2) = (P2 ∧ P); from specification heap-sep[zheap]% ⊦ (⌜bv⌝ ∧ P) * P2 = (⌜bv⌝ ∧ P * P2); (s)%and-ass: ⊦ ((P ∧ P3) ∧ P4) = (P ∧ P3 ∧ P4); from specification heap-sep[zheap]% ⊦ n + 0 = n; (s)% ⊦ n ≤ m → m + n0 - n = (m - n) + n0; (s)% ⊦ m + 1 ≠ 0; (s)% ⊦ m + 1 ≤ n ↔ m < n; (s)% ⊦ m ≤ m; (s)% ⊦ m + n ≤ m + n0 ↔ n ≤ n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic