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Proof step 16 from proof btree-clean-fwd (previous step)

(( r => mkznode(rp1, zbrar, false, false, nused) * bnode(r, zbrar, 0, nused, nused, height1, false, ri1, iast, alladrs1 -- adr, alladrs1 -- adr) * P1) )(zh), (( r2 => mkznode(rp0, zbrar0, false, false, nused) * bnode(r2, zbrar0, 0, nused, nused, height + 1, false, ri0, iast, alladrs0 -- adr, alladrs0 -- adr) * P0) )(zh2), nsize(nused, nstat), unmodified(adr, mkznode(rp1, zbrar, false, false, nused), iast), unmodified(adr, mkznode(rp0, zbrar0, false, false, nused), iast), adr ∈ iast, adr ∈ alladrs1, adr ∈ alladrs0, alladrs1 ⊆ dom iast, alladrs0 ⊆ dom iast, (r0 = null ⊃ P0(zh0);r2 = r0 ∧ zh2 = zh0), (r1 = null ⊃ P1(zh1);r = r1 ∧ zh = zh1), ∀ rp0, r0, adr, ri0, iast, as0, alladrs0, nstat, P0, zh0, rp1, r1, height1, ri1, as1, alladrs1, P1, zh1. ((btree(rp0, r0, adr, height, false, ri0, iast, as0, alladrs0, nstat) * P0))(zh0) ∧ ((btree(rp1, r1, adr, height1, false, ri1, iast, as1, alladrs1, nstat) * P1))(zh1) → height = height1 ∧ as0 = as1 ∧ ri0 = ri1 ∧ alladrs0 = alladrs1 ⊦ # alladrs1 = 0, # alladrs0 = 0, alladrs0 = ∅, alladrs1 = ∅, height1 = 0, height + 1 = height1 ∧ ri0 = ri1 ∧ alladrs0 = alladrs1

User applied rule constructor cut

And obtained the following new goals

Rule argument

var: height1

Additional information

Used simplifier rules: nat freely generated by 0, +1;;