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Proof step 31 from proof btree-inv-crash (previous step)

remove-refsize0(istore0) = istore0, ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh0), ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh1), inv(istore), refsize-cons(istore0, as0), refsize-cons(istore, as), adr ∈ istore, as0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), as ⊆ dom nodes(istore), as ⊆ alladrs, as0 ⊆ dom nodes(istore0), as0 ⊆ alladrs0, nodes(istore0) ⊆ nodes(remove-refsize0(crash(istore, istore0))), istore0 ⊑ istore ⊦ alladrs0 ⊆ dom nodes(remove-refsize0(crash(istore, istore0)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
remove-refsize0(istore0) = istore0, ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh1), ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh0), ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), inv(istore), refsize-cons(istore, as), refsize-cons(istore0, as0), adr ∈ istore, nodes(istore0) ⊆ nodes(remove-refsize0(crash(istore, istore0))), as0 ⊆ alladrs0, as0 ⊆ dom nodes(istore0), as ⊆ alladrs, as ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), as0 ⊆ dom nodes(istore), istore0 ⊑ istore ⊦ alladrs0 ⊆ dom nodes(remove-refsize0(crash(istore, istore0))), dom nodes(istore) ⊆ dom nodes(remove-refsize0(crash(istore, istore0)))

Rule argument

Additional information

Used simplifier rules: sub-ntrans: ⊦ as ⊆ as0 ∧ ¬ as ⊆ as1 → ¬ as0 ⊆ as1; (forward) from specification set-basic[node-store]