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Proof step 4 from proof btree-inv-crash (previous step)

remove-refsize0(istore0) = istore0, ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh0), inv(istore), refsize-cons(istore, as), refsize-cons(istore0, as0), adr ∈ istore, as0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), as ⊆ dom nodes(istore), as ⊆ alladrs, as0 ⊆ dom nodes(istore0), as0 ⊆ alladrs0, istore0 ⊑ istore ⊦ ∃ height, dirty, as, alladrs. ((btree(null, null, adr, height, dirty, fi, nodes(remove-refsize0(crash(istore, istore0))), as, alladrs, ok) * true))(zh1) ∧ refsize-cons(remove-refsize0(crash(istore, istore0)), as) ∧ adr ∈ remove-refsize0(crash(istore, istore0)) ∧ alladrs ⊆ dom nodes(remove-refsize0(crash(istore, istore0)))

User applied rule exists right

And obtained the following new goals

Proof step 5:
remove-refsize0(istore0) = istore0, ((btree(null, null, adr, height0, false, fi, nodes(istore0), as0, alladrs0, ok) * true))(zh0), ((btree(null, rp, adr, height, dirty, ri, nodes(istore), as, alladrs, ok) * true))(zh0), inv(istore), refsize-cons(istore0, as0), refsize-cons(istore, as), adr ∈ istore, as0 ⊆ alladrs0, as0 ⊆ dom nodes(istore0), as ⊆ alladrs, as ⊆ dom nodes(istore), alladrs0 ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore), as0 ⊆ dom nodes(istore), istore0 ⊑ istore ⊦ ((btree(null, null, adr, height0, false, fi, nodes(remove-refsize0(crash(istore, istore0))), as0, alladrs0, ok) * true))(zh1) ∧ refsize-cons(remove-refsize0(crash(istore, istore0)), as0) ∧ adr ∈ remove-refsize0(crash(istore, istore0)) ∧ alladrs0 ⊆ dom nodes(remove-refsize0(crash(istore, istore0)))

Rule argument

pos: right 1 terms: height0, false, as0, alladrs0 abort: F discard: T computed: F

Additional information

Used terms: height0, false, as0, alladrs0