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Proof step 11 from proof btree-inv-format (previous step)

⊦ (( btree (null, null, @(n, m0, m1), 0, false, ∅, nodes((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)]), ∅ ++ @(n, m0, m1), ∅ ++ @(n, m0, m1), ok) * true) )(zh) ∧ refsize-cons((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)], ∅ ++ @(n, m0, m1))

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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