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Proof step 9 from proof btree-inv-format (previous step)

⊦ ∃ height, as, alladrs. (( btree (null, null, @(n, m0, m1), height, false, ∅, nodes((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)]), as, alladrs, ok) * true) )(zh) ∧ refsize-cons((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)], as) ∧ alladrs ⊆ dom nodes((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)])

User applied rule exists right

And obtained the following new goals

Proof step 10:
⊦ (( btree (null, null, @(n, m0, m1), 0, false, ∅, nodes((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)]), ∅ ++ @(n, m0, m1), ∅ ++ @(n, m0, m1), ok) * true) )(zh) ∧ refsize-cons((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)], ∅ ++ @(n, m0, m1)) ∧ ∅ ++ @(n, m0, m1) ⊆ dom nodes((∅)[n, indexblock(indexnode(mkbrarray(BRANCH_SIZE), true, 0) ', @(m0, m1) ', m1)])

Rule argument

pos: right 1 terms: 0, ∅ ++ @(n, m0, m1), ∅ ++ @(n, m0, m1) abort: F discard: T computed: F

Additional information

Used terms: 0, ∅ ++ @(n, m0, m1), ∅ ++ @(n, m0, m1)