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Proof step 23 from proof btree-inv-remove-refsize0 (previous step)

zh[rp] = mkznode(rp0, zbrar, boolvar, dirty, nused), ((btree(null, rp, adr, height, false, ri, nodes(istore), alladrs, alladrs, ok) * true))(zh), ((btree(null, null, adr, height, false, ri, nodes(istore0), alladrs, alladrs, ok) * true))(zh), inv(istore0), inv(istore), refsize-cons(istore, alladrs), refsize-cons(istore0, alladrs), adr ∈ istore, alladrs ⊆ dom nodes(istore), alladrs ⊆ dom nodes(istore0), istore0 ⊑ istore, rp = null ∨ ¬ dirty, ¬ dirty ∨ rp = null ⊦ ∃ height, as, alladrs. ((btree(null, null, adr, height, false, ri, nodes(remove-refsize0(istore)), as, alladrs, ok) * true))(zh) ∧ refsize-cons(remove-refsize0(istore), as) ∧ alladrs ⊆ dom nodes(remove-refsize0(istore))

User applied rule exists right

And obtained the following new goals

Proof step 24:
zh[rp] = mkznode(rp0, zbrar, boolvar, dirty, nused), ((btree(null, null, adr, height, false, ri, nodes(istore0), alladrs, alladrs, ok) * true))(zh), ((btree(null, rp, adr, height, false, ri, nodes(istore), alladrs, alladrs, ok) * true))(zh), inv(istore), inv(istore0), refsize-cons(istore0, alladrs), refsize-cons(istore, alladrs), adr ∈ istore, alladrs ⊆ dom nodes(istore0), alladrs ⊆ dom nodes(istore), istore0 ⊑ istore, ¬ dirty ∨ rp = null, rp = null ∨ ¬ dirty ⊦ ((btree(null, null, adr, height, false, ri, nodes(remove-refsize0(istore)), alladrs, alladrs, ok) * true))(zh) ∧ refsize-cons(remove-refsize0(istore), alladrs) ∧ alladrs ⊆ dom nodes(remove-refsize0(istore))

Rule argument

pos: right 1 terms: height, alladrs, alladrs abort: F discard: T computed: F

Additional information

Used terms: height, alladrs, alladrs