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Proof step 12 from proof btree-null-or-clean-below (previous step)

((r => mkznode(rp, zbrar0, height = 0, false, nused) * bnode(r, zbrar0, 0, nused, nused, height, false, ri, iast, as -- adr, alladrs -- adr) * P) )(zh0), nsize(nused, nstat), unmodified(adr, mkznode(rp, zbrar0, height = 0, false, nused), iast), adr ∈ as, adr ∈ alladrs ⊦ # as = 0, # alladrs = 0, alladrs = ∅, as = ∅, ∃ zbrar1, nused0. nsize(nused0, nstat) ∧ unmodified(adr, mkznode(rp, zbrar1, height = 0, false, nused0), iast) ∧ (( r => mkznode(rp, zbrar1, height = 0, false, nused0) * bnode(r, zbrar1, 0, nused0, nused0, height, false, ri, iast, as -- adr, alladrs -- adr) * P) )(zh0)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 5 terms: zbrar0, nused

Additional information

Used simplifier rules: sep-ass: ⊦ (P * P3) * P4 = P * P3 * P4; from specification heap-sep[zheap]%sep-com: ⊦ P * P2 = P2 * P; from specification heap-sep[zheap] Used terms: zbrar0, nused