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Proof step 9 from proof btree-null (previous step)

((r => mkznode(rp, zbrar, height = 0, false, nused) * bnode(r, zbrar, 0, nused, nused, height, false, ri, iast, as -- adr, alladrs -- adr) * true) )(zh), nsize(nused, nstat), unmodified(adr, mkznode(rp, zbrar, height = 0, false, nused), iast), adr ∈ as, adr ∈ alladrs, adr ∈ iast, as ⊆ alladrs, as ⊆ dom iast ⊦ # as = 0, # alladrs = 0, alladrs = ∅, as = ∅, ∃ r0, zh0, zbrar0, nused0. nsize(nused0, nstat) ∧ unmodified(adr, mkznode(rp, zbrar0, height = 0, false, nused0), iast) ∧ (( r0 => mkznode(rp, zbrar0, height = 0, false, nused0) * bnode(r0, zbrar0, 0, nused0, nused0, height, false, ri, iast, as -- adr, alladrs -- adr) * true) )(zh0)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 5 terms: r, zh, zbrar, nused

Additional information

Used simplifier rules: sep-ass: ⊦ (P * P3) * P4 = P * P3 * P4; from specification heap-sep[zheap]%sep-com: ⊦ P * P2 = P2 * P; from specification heap-sep[zheap]% ⊦ ((P1 * P2))(zh) → ((true * P2))(zh); (s) Used terms: r, zh, zbrar, nused