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Proof step 1 from proof btree-repl-dirty-address (conclusion)

⊦ ¬ adr1 ∈ alladrs ∧ r ∈ zh ∧ zh[r].dirty ∧ ((btree(rp, r, adr0, height, true, ri, iast, as, alladrs, nstat) * P))(zh) → ((btree(rp, r, adr1, height, true, ri, iast, as, (alladrs -- adr0) ++ adr1, nstat) * P))(zh)

System applied rule normalize

And obtained the following new goals

Proof step 2:
((btree(rp, r, adr0, height, true, ri, iast, as, alladrs, nstat) * P))(zh), zh[r].dirty, r ∈ zh ⊦ ((btree(rp, r, adr1, height, true, ri, iast, as, (alladrs -- adr0) ++ adr1, nstat) * P))(zh), adr1 ∈ alladrs

Proof step 1 from proof btree-repl-dirty-address (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information