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Proof step 2 from proof btree-reset-root (previous step)

((btree(rp, r, adr, height, false, ri, iast, as, alladrs, ok) * true))(zh) ⊦ ((btree(rp, null, adr, height, false, ri, iast, as, alladrs, ok) * true))(zh)

User applied rule apply lemma

And obtained the following new goals

Proof step 3:
⊦ ((btree(rp, r, adr, height, false, ri, iast, as, alladrs, ok) * P))(zh) → ((btree(rp, null, adr, height, false, ri, iast, as, alladrs, ok) * true * P))(zh)

Rule argument

spec: <toplevel> name: btree-reset-root-frame seq: ⊦ (( btree (rp, r, adr, height, false, ri, iast, as, alladrs, ok) * P) )(zh) → (( btree (rp, null, adr, height, false, ri, iast, as, alladrs, ok) * true * P) )(zh) subst: [rp, r, adr, height, ri, iast, as, alladrs, P, zh] → [rp, r, adr, height, ri, iast, as, alladrs, true, zh]

Additional information

Used simplifier rules: sep-ass: ⊦ (P * P3) * P4 = P * P3 * P4; from specification heap-sep[zheap]%sep-com: ⊦ P * P2 = P2 * P; from specification heap-sep[zheap]% ⊦ ((P1 * P2))(zh) → ((true * P2))(zh); (s)% ⊦ true * true = true; (s) Used terms: rp, r, adr, height, ri, iast, as, alladrs, true, zh