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Proof step 7 from proof btree-restrict-union-proper (previous step)

((btree(rp, r, adr, height, dirty, ri, iast, asar[n], alladrs, nstat) * P))(zh), n < # asar, asar[n] ⊆ alladrs, asar[n] ⊆ dom iast ⊦ ((btree(rp, r, adr, height, dirty, ri, iast | union(asar, 0, # asar), asar[n], alladrs, nstat) * P))(zh), iast | asar[n] ⊆ iast | union(asar, 0, # asar) ∧ ((btree(rp, r, adr, height, dirty, ri, iast, asar[n], alladrs, nstat) * P))(zh)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
((btree(rp, r, adr, height, dirty, ri, iast, asar[n], alladrs, nstat) * P))(zh), n < # asar, asar[n] ⊆ dom iast, asar[n] ⊆ alladrs ⊦ ((btree(rp, r, adr, height, dirty, ri, iast | union(asar, 0, # asar), asar[n], alladrs, nstat) * P))(zh), iast | asar[n] ⊆ iast | union(asar, 0, # asar)

Proof step 7 from proof btree-restrict-union-proper (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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