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Proof step 20 from proof btree-sub-clean-next (previous step)

zbrar[n0] = mkzbranch(key, adr, r2), zh[zbrar[n].child] = mkznode(r1, zbrar0, boolvar1, boolvar2, m0), zh[r] = mkznode(r0, zbrar, false, boolvar0, m), zh[r2] = mkznode(r3, zbrar1, boolvar, boolvar3, m1), boolvar3, n0 < m, r ∈ zh, r2 ∈ zh, n0 ≤ n, n < m ∧ zbrar[n].branch? ∧ zbrar[n].child ∈ zh → ¬ boolvar2, ∀ n0. n0 < m ∧ n0 < n ∧ zbrar[n0].branch? ∧ zbrar[n0].child ∈ zh → ¬ zh[zbrar[n0].child].dirty ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
zh[r2] = mkznode(r3, zbrar1, boolvar, true, m1), zh[r] = mkznode(r0, zbrar, false, boolvar0, m), zh[zbrar[n].child] = mkznode(r1, zbrar0, boolvar1, boolvar2, m0), zbrar[n0] = mkzbranch(key, adr, r2), n0 < m, r2 ∈ zh, r ∈ zh, n0 ≤ n, n < m ∧ zbrar[n].branch? ∧ zbrar[n].child ∈ zh → ¬ boolvar2, ∀ n0. n0 < m ∧ n0 < n ∧ zbrar[n0].branch? ∧ zbrar[n0].child ∈ zh → ¬ zh[zbrar[n0].child].dirty ⊦

Proof step 20 from proof btree-sub-clean-next (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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