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Proof step 7 from proof btree-sub-clean-next (previous step)

zh[r] = mkznode(r0, zbrar, boolvar, boolvar0, m), btree-sub-clean(r, n, zh) ⊦ r ∈ zh ∧ (¬ boolvar → (∀ n0. n0 < m ∧ ¬ n < n0 ∧ zbrar[n0].branch? ∧ zbrar[n0].child ∈ zh → ¬ zh[zbrar[n0].child].dirty)) ↔ ¬ boolvar ∧ n < m ∧ zbrar[n].branch? ∧ zbrar[n].child ∈ zh → ¬ zh[zbrar[n].child].dirty

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
zh[r] = mkznode(r0, zbrar, boolvar, boolvar0, m), zh[zbrar[n].child] = mkznode(r1, zbrar0, boolvar1, boolvar2, m0), btree-sub-clean(r, n, zh) ⊦ r ∈ zh ∧ (¬ boolvar → (∀ n0. n0 < m ∧ ¬ n < n0 ∧ zbrar[n0].branch? ∧ zbrar[n0].child ∈ zh → ¬ zh[zbrar[n0].child].dirty)) ↔ ¬ boolvar ∧ n < m ∧ zbrar[n].branch? ∧ zbrar[n].child ∈ zh → ¬ boolvar2

Rule argument

spec: znode name: elim seq: ⊦ ( ( (r = znd.parent ∧ zbrar = znd.zbranches) ∧ (boolvar ↔ znd.leaf)) ∧ (boolvar0 ↔ znd.dirty)) ∧ m = znd.usedsize ↔ znd = mkznode(r, zbrar, boolvar, boolvar0, m) subst: [znd, r, zbrar, boolvar, boolvar0, m] → [zh[zbrar[n].child], r1, zbrar0, boolvar1, boolvar2, m0]

Additional information

Used simplifier rules: ⊦ ( ( (r = znd.parent ∧ zbrar = znd.zbranches) ∧ (boolvar ↔ znd.leaf)) ∧ (boolvar0 ↔ znd.dirty)) ∧ m = znd.usedsize ↔ znd = mkznode(r, zbrar, boolvar, boolvar0, m); (elim) Used terms: zh[zbrar[n].child], r1, zbrar0, boolvar1, boolvar2, m0