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Proof step 5 from proof btree-sub-clean-write-branches (previous step)

zh[r] = mkznode(r0, zbrar, boolvar, boolvar0, m), n < # zbrar, btree-sub-clean(r, n, zh) ⊦ zh[zbrar[n].child].dirty, btree-sub-clean(r, n + 1, zh[r, mkznode(r0, zbrar[n, mkzbranch(key, adr, zbrar[n].child)], boolvar, boolvar0, m)])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
zh[r] = mkznode(r0, zbrar, boolvar, boolvar0, m), zh[zbrar[n].child] = mkznode(r1, zbrar0, boolvar1, boolvar2, m0), ¬ boolvar2, n < # zbrar, btree-sub-clean(r, n, zh) ⊦ btree-sub-clean(r, n + 1, zh[r, mkznode(r0, zbrar[n, mkzbranch(key, adr, zbrar[n].child)], boolvar, boolvar0, m)])

Rule argument

spec: znode name: elim seq: ⊦ ( ( (r = znd.parent ∧ zbrar = znd.zbranches) ∧ (boolvar ↔ znd.leaf)) ∧ (boolvar0 ↔ znd.dirty)) ∧ m = znd.usedsize ↔ znd = mkznode(r, zbrar, boolvar, boolvar0, m) subst: [znd, r, zbrar, boolvar, boolvar0, m] → [zh[zbrar[n].child], r1, zbrar0, boolvar1, boolvar2, m0]

Additional information

Used simplifier rules: ⊦ ( ( (r = znd.parent ∧ zbrar = znd.zbranches) ∧ (boolvar ↔ znd.leaf)) ∧ (boolvar0 ↔ znd.dirty)) ∧ m = znd.usedsize ↔ znd = mkznode(r, zbrar, boolvar, boolvar0, m); (elim) Used terms: zh[zbrar[n].child], r1, zbrar0, boolvar1, boolvar2, m0