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Proof step 2 from proof inter-subseteq-weaken (previous step)

as ⊆ as2, as0 ∩ as2 ⊆ as1 ⊦ as0 ∩ as ⊆ as1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: inter-subseteq-simp: ⊦ as0 ∩ as ⊆ as1 ∩ as ↔ as0 ∩ as ⊆ as1;% ⊦ as ∩ as0 ⊆ as; (s)%int-c: ⊦ as ∩ as0 = as0 ∩ as; from specification set-union[node-store]%int-a: ⊦ (as ∩ as0) ∩ as1 = as ∩ as0 ∩ as1; from specification set-union[node-store]%sub-ntrans-01: ⊦ as ⊆ as0 ∧ ¬ as1 ⊆ as0 → ¬ as1 ⊆ as; (forward) from specification set-basic[node-store]