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Proof step 1 from proof inter-union-diff-subseteq (conclusion)
⊦ as1 ∩ as3 ⊆ as → ((as0 ∪ (as1 \ as2)) ∩ as3 ⊆ as ↔ as0 ∩ as3 ⊆ as)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
as1 ∩ as3 ⊆ as ⊦ (as0 ∪ (as1 \ as2)) ∩ as3 ⊆ as ↔ as0 ∩ as3 ⊆ as
Rule argument
Additional information