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Proof step 2 from proof restrict-add-at (previous step)

iast0[adr] = ind, adr ∈ as, adr ∈ iast0, iast0 | as ⊆ iast1 ⊦ iast1[adr] = iast0[adr]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
adr ∈ as, adr ∈ iast0, iast0 | as ⊆ iast1 ⊦ # as = 0, iast1[adr] = iast0[adr], as = ∅

Rule argument

Additional information

Used simplifier rules: size-zero-01: ⊦ as ≠ ∅ → # as ≠ 0; (forward) from specification set-basic[node-store]%ne-01: ⊦ adr ∈ as → as ≠ ∅; (forward) from specification set-basic[node-store]