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Proof step 7 from proof restrict-add-subseteq-at (previous step)

(iast0 | (as ++ adr))[adr] = iast1[adr], adr ∈ iast0, adr ∈ iast1 ⊦ iast1[adr] = iast0[adr]

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: store+set, inst: index-store-address-store name: restrict-at seq: ⊦ adr ∈ iast ∧ adr ∈ as → (iast | as)[adr] = iast[adr] subst: [adr, as, iast] → [adr, as ++ adr, iast0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ adr ∈ as ++ adr0 ↔ adr = adr0 ∨ adr ∈ as; (s) Used terms: adr, as ++ adr, iast0