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Proof step 1 from proof restrict-add-subseteq-in (conclusion)
⊦ iast0 | (as ++ adr) ⊆ iast1 ∧ adr ∈ iast0 → adr ∈ iast1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
adr ∈ iast0, iast0 | (as ++ adr) ⊆ iast1 ⊦ adr ∈ iast1
Rule argument
Additional information