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Proof step 14 from proof sep-forall-reduce-true (previous step)

((nP(n + n0) * P))(zh), ((nP2(n + m0) * true * P0 * nP ⊗_(n, m0)))(zh), ((nP ⊗_(n, m0) * nP(n + m0) * P0))(zh), n0 < m0, ∀ n0, P. ¬ m0 < n0 ∧ ((nP(n + n0) * P))(zh) → ((nP2(n + n0) * true * P))(zh) ⊦ ((nP2(n + n0) * true * P))(zh), ((nP2 ⊗_(n, m0) * nP2(n + m0) * true * P0))(zh)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0, P

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; (s) Used terms: n0, P