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Proof step 19 from proof recovery (previous step)

syn ↔ true, fi = fi0, ginval = ginval2, ginval0 = ginval3, gstore = gstore1, gstore0 = crash(gstore4, gstore1, ginval3, nx1), gstore3 = crash(gstore4, gstore1, ginval3, nx1), maxino = maxino1, nx = nx1, remove-refsize0(gstore1) = gstore1, remove-refsize0(istore1) = istore1, elems nx1 ∩ ginval3 = ∅, dom gstore1 ∪ elems nx1 = dom gstore4 ∪ ginval3, btree-inv(rp1, adr2, istore2, istore1, zh, fi1, fi0), btree-inv(rp1, adr2, istore2, istore1, zh, ri, fi3), inv(gstore4 \ ginval3), inv(gstore1), inv(istore2), inv(istore1), inv(crash(gstore4, gstore1, ginval3, nx1) \ ginval3), ri-inj(fi1), ri-inj(fi0), istore1 ⊑ istore2, pstate1.journal? → nx1 ≠ [] ∧ pstate1.lnum = nx1.last ∧ pstate1.lnum ∈ gstore4, pstate1.index? → pstate1.lnum ∈ istore2 ⊦ ⟨index+persistence_recover#(; maxino3, nx3, ginval6, fi0, fi, ginval3, gstore3, gstore1, nx1, maxino1, ginval2, syn; err0)⟩ ( ginval3 = ginval0 ∧ gstore3 = gstore0 ∧ gstore1 = gstore ∧ nx1 = nx3 ∧ maxino1 = maxino3 ∧ ginval2 = ginval6 ∧ btree-inv(null, adr2, remove-refsize0(crash(istore2, istore1)), istore1, zh0, fi0, fi) ∧ syn ∧ maxino = maxino3 ∧ nx = nx3 ∧ ginval = ginval6 ∧ ESUCCESS = err0), dups(nx1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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