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Proof step 14 from proof refine-get-block-free-size (previous step)

syn ↔ syn0, ginval = ginval2, gstore = gstore2, istore = istore1, istore0 = istore2, maxino = maxino0, nx = nx0, remove-refsize0(istore1) = istore1, remove-refsize0(gstore2) = gstore2, elems nx0 ∩ ginval0 = ∅, dom gstore2 ∪ elems nx0 = dom gstore0 ∪ ginval0, btree-inv(rp, adr, istore2, istore1, zh, fi, fi0), inv(istore1), inv(istore2), inv(gstore2), inv(gstore0 \ ginval0), ri-inj(fi0), ri-inj(fi), istore1 ⊑ istore2, pstate = unbuffered → syn0, pstate.index? → pstate.lnum ∈ istore2, pstate.journal? → nx0 ≠ [] ∧ pstate.lnum = nx0.last ∧ pstate.lnum ∈ gstore0 ⊦ ⟪choose n with n ≤ LEB_SIZE in n0 := n⟫ ⟨index_get_block_free_size#(fi, fi0, ginval0, gstore0, gstore2, nx0, maxino0, ginval2, syn0; ; n1)⟩ (n0 = n1), pstate = unbuffered, dups(nx0)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

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