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Proof step 23 from proof refine-get-block-free-size (previous step)

remove-refsize0(gstore2) = gstore2, remove-refsize0(istore1) = istore1, elems nx0 ∩ ginval0 = ∅, dom gstore2 ∪ elems nx0 = dom gstore0 ∪ ginval0, btree-inv(rp, adr, istore2, istore1, zh, fi2, fi1), inv(gstore0 \ ginval0), inv(gstore2), inv(istore2), inv(istore1), ri-inj(fi2), ri-inj(fi1), n1 ≤ LEB_SIZE, istore1 ⊑ istore2, pstate.index? → pstate.lnum ∈ istore2 ⊦ n1 ≤ LEB_SIZE ∧ ⟨n := n1⟩ (n1 = n), pstate = unbuffered, pstate.journal?, dups(nx0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
remove-refsize0(istore1) = istore1, remove-refsize0(gstore2) = gstore2, elems nx0 ∩ ginval0 = ∅, dom gstore2 ∪ elems nx0 = dom gstore0 ∪ ginval0, pstate ≠ unbuffered, btree-inv(rp, adr, istore2, istore1, zh, fi2, fi1), inv(istore1), inv(istore2), inv(gstore2), inv(gstore0 \ ginval0), ri-inj(fi1), ri-inj(fi2), n1 ≤ LEB_SIZE, istore1 ⊑ istore2, ¬ pstate.journal?, ¬ dups(nx0), pstate.index? → pstate.lnum ∈ istore2 ⊦ ⟨n := n1⟩ (n1 = n)

Proof step 23 from proof refine-get-block-free-size (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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